Jun 13, 2021 answer. answered. A rain gutter is to be constructed of aluminum sheets 12 inches wide. After marking off a length of 4 inches from each edge, this length is bent up at an angle θ. The area A of the opening may be expressed as the function: A (θ) = 16 sin θ

May 06,018 answered (10.02 lc) a rain gutter is to be constructed of aluminum sheets 12 inches wide. after marking off a length of 4 inches from each edge, this length is bent up at an angle θ. the area of the opening may be expressed as the function: a (θ) = 16 sin θ ⋅ (cos θ + 1). if θ = 30°, what is the area of the opening?

Jul 20, 2021 A rain gutter is to be constructed of aluminum sheets of 12 inches wide. After marking off a length of 4 inches from each edge, this length is bent up at an angle 0. The area of the opening may be expressed as the function A0= 16 sin0(cos0+1) if 0=30 what is the area of the

Sep 20, 2021 Mathematics, 20.09.:01 s. A rain gutter is to be constructed of aluminum sheets 12 inches wide. After marking off a length of 4 inches from each edge, this length is bent up at an angle θ. The area A of the opening may be expressed as the function: A (θ) = 16 sin θ ⋅ (cos θ +

A rain gutter is to be constructed of aluminum sheets 12 incheswide. After marking off a length of 4 inches from each edge, this lengthis bent up at an angle x (see the figure below). The cross sectional area of the gutter changes as the angle x changes. The goal is to understand how the cross sectional area changes as a function of x,and to find the largest possible cross sectional area in order to

Nov 10, 2021 We are given a rain gutter made from folding a 12 inch wide aluminum sheet to an angle theta. The area of the opening is expressed as A (Θ) = 16 sin Θ (cos Θ + 1) where Θ = 60°. we can just substitute directly the angle in degrees mode in the calculator and

SOLUTION: A rain gutter is made from sheets of aluminum that are 12 inches wide by turning up the edges to form right angles. Determine the depth of the gutter that will maximize its. 12 inches wide by turning up the edges to form right angles. cross-sectional

A rain gutter is to be constructed from a metal sheet of width 3w by bending up one third of the sheet on each side through an angle

A rain gutter is to be constructed of metal sheets 3 feet wide. Given the configuration, find the angle theta for which maximum rain water can flow through the

A rain gutter is to be constructed from Aluminum sheet 12 inches wide, after marking off a length of 4 inches each edge. This length is bent angle {eq}heta

Question: Constructing A Rain Gutter: A Rain Gutter Is To Be Constructed Of Aluminum Sheets 12 Inches Wide. After Marking Off A Length Of 4 Inches From Each Edge, This Length Is Bent Up At An Angle Theta. (See The Illustration) The Area A Of The Opening As A Function Of Theta Is Given By A = 16 Sin Theta (cos Theta + 1) 0 Degree < Theta < 90 Degree What Is The

Constructing a Rain Gutter A rain gutter is to be constructed of aluminum sheets 12 inches wide. After marking off length of 4 in from each edge, this length is bent up at an angle ?. a) Show that the area A of the opening or cross-section (as shown on the illustration) of the gutter as a function of ? is given by 4 (?)-16sin0 (cos ? +1),

Jun 05, 2021 (10.02 lc) a rain gutter is to be constructed of aluminum sheets 12 inches wide. after marking off a length of 4 inches from each edge, this length is bent up at an angle θ. the area of the opening may be expressed as the function: a(θ) = 16 sin θ ⋅

A simple rain gutter is constructed using a sheet of aluminum that is 40cm wide. A simple rain gutter is constructed using a sheet of aluminum that is 40cm wide. The edges are turned up to form right angles. Determine the depth of the gutter that will maximize the cross-sectional area (allowing the greatest amount of water to flow).I don\'t know

Jun 20, 2021 Correct answers: 2 question: A rain gutter is to be constructed of aluminum sheets 12 inches wide. After marking off a length of 4 inches from each edge, this length is bent up at an angle 0. The area of the opening may be expressed as the function: A(O) = 16 sin 0 - (cos 0 + 1). If 0 = 30°, what is the area of the opening? (6 points) O 14.9 in 2 O 16.0 O 19.3 in 2 O 20.8

Apr 11, 2021 Arain gutter is to be constructed of aluminum sheets 12 inches wide. after marking off a length of 4 inches from each edge, this length is bent up at an angle θ. the area a of the opening may be expressed as the function: a(θ) = 16 sin θ (cos θ + 1). if θ = 60°, what is the area of the

A rain gutter is to be constructed from a metal sheet of width 3w by bending up one third of the sheet on each side through an angle theta. How should theta be chosen so that the gutter will carry

Apr 04, 2012 A simple rain gutter is constructed using a sheet of aluminum that is 40cm wide. The edges are turned up to form right angles. Determine the depth of the gutter that will maximize the cross-sectional area (allowing the greatest amount of water to flow). I don\'t know where and how to start. please help and thank

A rain gutter is made from sheets of aluminum that are 18 inches wide by turning up the edges to form right angles. Determine the depth of the gutter that will maximize its cross-sectional area and allow the greatest amount of water to flow.: Let x = depth of the gutter then 18-2x = width of the gutter: Cross section area: A = depth * width A

Jul 27, 2021 A rain gutter is to be constructed of aluminum sheets 12 inches wide. After marking off a length of 4 inches from each edge, this length is bent up at an angle Θ. The area A of the opening may be expressed as the function: A(Θ) = 16 sin Θ (cos Θ +

Arain gutter is to be constructed of aluminum sheets 12 inches wide. after marking off a length of 4 inches from each edge, this length is bent up at an angle θ. the area a of the opening may be expressed as the function: a(θ) = 16 sin θ ⋅ (cos θ + 1). if θ = 90°, what is the area of the

Question : A rain gutter is formed by bending up the sides by x inches of a 30-inch wide rectangular metal sheet as shown in the figure. (a) Find a function that models the cross-sectional area of the gutter in terms of x. (b) Find the value of x that maximizes the cross-sectional area of the

Nov 15, 2010 A long rectangular sheet of metal, 12 inches wide, is to be made into a rain gutter by turning up two sides so that they are perpendicular to the sheet. Find the dimensions of the rectangular box that would contain a max volume if it were constructed from this piece of metal by the average amount of rain per year in Greenville is 49